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## Homework Statement

The figure shows an electron entering a parallel-plate capacitor with a speed of 5.4×10

^{6}m/s. The electric field of the capacitor has deflected the electron downward by a distance of 0.618cm at the point where the electron exits the capacitor.

**Find the magnitude of the electric field in the capacitor.**

## Homework Equations

f=ma

f=k(q/r

^{2})

## The Attempt at a Solution

I'm trying to figure out how to gauge the force applied from the field, which I'm assuming can be taken from the displacement & speed traveled. I'm also assuming that gravity isn't a factor here, so if E=f/q

_{0}where am I getting my f from?

Relevant data:

length of capacitor: 2.25E-2m

e

^{-}

_{m}: 9.11E-31kg

e

^{-}

_{q}: 1.60E-19C

e

^{-}

_{v}: 5.4E6m/s

[tex]\theta[/tex]:15.36[tex]\circ[/tex]

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