# Electric Field Magnitude

## Homework Statement

The figure shows an electron entering a parallel-plate capacitor with a speed of 5.4×106m/s. The electric field of the capacitor has deflected the electron downward by a distance of 0.618cm at the point where the electron exits the capacitor.

Find the magnitude of the electric field in the capacitor.

f=ma
f=k(q/r2)

## The Attempt at a Solution

I'm trying to figure out how to gauge the force applied from the field, which I'm assuming can be taken from the displacement & speed traveled. I'm also assuming that gravity isn't a factor here, so if E=f/q0 where am I getting my f from?

Relevant data:
length of capacitor: 2.25E-2m
e-m: 9.11E-31kg
e-q: 1.60E-19C
e-v: 5.4E6m/s
$$\theta$$:15.36$$\circ$$

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