(a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in Figure P15.10.
That hard to read number is 3 cm.
(b) If a charge of -3.50 µC is placed at this point, what are the magnitude and direction of the force on it?
E = Keq/r^2
The Attempt at a Solution
I tried using the formula but was incorrect.
E = 8.99e9(1.5e-6)/.003^2
I used 1.5e-6 for q because i thought you need to use the middle charge and i think the r is .003 m since from -2uC to 1.5uC its 2 cm but it say its 1 cm to the left of the middle charge so i thought i add the distance.
For B i am not even sure how to do since i dont even understand how to do part a.