1. The problem statement, all variables and given/known data Two tiny objects with equal charges of 63.0 µC are placed at two corners of a square with sides of 0.260 m, as shown. How far above and to the left of the corner of the square labeled A would you place a third small object with the same charge so that the electric field is zero at A? 2. Relevant equations E = KQ/r^2 3. The attempt at a solution I first solved for E net on point A. My values were Enetx = 2.962 x 10^6 Enety = 1.13 x 10^7 Magnitude of Etotal = 1.17 x 10^7 angle formed : 75.3 degrees Now I tried two alternate solutions, but in the end I got the wrong answer still for both tries. E = kq/r^2 r = sqrt(kq/E) r = sqrt(k(63e-6)/1.17e6) r=0.22m dx=0.22cos75.3=0.0558 dy=0.22sin75.3=0.213 That one was wrong, so I tried finding the value of r using the components of the electric field rx= sqrt(k(63e-6)/2.962e6) ry=sqrt(k(63e-6)/1.13e7) rx =0.43m ry=0.22m still wrong, i need help because I'm not sure what I'm doing wrong.