- #1

tuggler

- 45

- 0

## Homework Statement

I am suppose to find an expression for the electric field of a ring.

## Homework Equations

[tex]E =\frac{Kq}{r^2}[/tex]

## The Attempt at a Solution

I calculated my results and I reached up to this:

[tex]\frac{Kx\Delta q}{(R^2 + x^2)}^{3/2}[/tex] where R = radius, x = distance, K = constant, q = charge.

And then I looked at my book and noticed they integrated with respect to [tex]\Delta q [/tex] which got me confused because when I calculated the electric field due to a line charge [tex]\Delta q [/tex] it wasn't considered a geometric property. The final expression the book gave [tex]\frac{Kx q}{(R^2 + x^2)}^{3/2}.[/tex]

How come they can integrate with respect to [tex]\Delta q [/tex] in this case but not a line charge?

For example, when I was measuring the electric field of a line of charge I got the expression [tex]\sum \frac{d \Delta Q}{(y_1^2 + d^2)^{3/2}}[/tex] but with that expression I couldn't integrate over [tex]\Delta Q[/tex] because the book said it is not a geometric quantity so I had to replace [tex]\Delta Q[/tex] with [tex]\Delta Q = Q/L \Delta y.[/tex] I don't understand why we had to change it with the field of a line but not with a disk?

The book did the same thing with an electric field of a ring as they did with the line of charge by replacing [tex]\Delta Q[/tex] with the density over the surface area [tex] 2r\pi dr[/tex].

Last edited: