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Electric Field of metal

  1. Jun 7, 2014 #1
    1. The problem statement, all variables and given/known data

    A sealed metal can is placed in a uniform external electric field of 10 N/C . The field points along the +x direction. The can is 20cm in length and 10cm in diameter. What's the value of the electric field at the center of the can?

    2. Relevant equations

    3. The attempt at a solution
    i'm pretty sure this has something to do with Gauss' law but I'm not sure how to relate electric flux back to electric field magnitude especially without a charge?
     
  2. jcsd
  3. Jun 7, 2014 #2

    hilbert2

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    Doesn't the metal can act as a Faraday cage?
     
  4. Jun 7, 2014 #3
    i honestly have no clue what that is, i don't think we have gone over that yet.

    i was just assuming this was a gaussian surface of some kind maybe because it's enclosed?
     
  5. Jun 7, 2014 #4
    i honestly have no clue what that is, i don't think we have gone over that yet.

    i was just assuming this was a gaussian surface of some kind maybe because it's enclosed?
     
  6. Jun 7, 2014 #5

    hilbert2

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    In an electrostatic situation, the electric field inside a conductor material is always zero. Because if there were a nonzero field, electric current would be induced and it would not be a static situation. The same applies if the conducting object is hollow.

    http://en.wikipedia.org/wiki/Faraday_cage
     
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