How Does Charge Distribution Affect Electric Field Calculation on a Disk?

In summary, the conversation was about finding the magnitude of electric field produced by a nonconducting disk with a charge of -5.00 nC on one of its faces at a point 3.00 cm from its center. The equation used was E=kq/r^2 and it was suggested to integrate over the disk using the electric field due to the charge on an infinitely thin ring surrounding the center of the disk.
  • #1
mcaro
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0

Homework Statement



A charge of -5.00 nC is spread uniformly over the surface of one face of a nonconducting disk of radius 1.15 cm. Find the magnitude of the electric field this disk produces at a point P on the axis of the disk a distance of 3.00 cm from its center.

Homework Equations



Surface area element for a disk [sigma]= Q / A

See attachments

The Attempt at a Solution



So I plugged the numbers in accordingly, had no luck.

I appreciate the help.
 

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  • #2
I'm working on uploading a picture of my attempt.
 
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... uploaded
 

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  • #4
mcaro said:
Surface area element for a disk [sigma]= Q / A

That equation only applies for infinitely large plates. This disk is not infinitely large.

Try using E=kq/r^2 to get the electric field due to the charge on one infinitely thin ring surrounding the center of the disk. Then, integrate over the disk.
 

What is an electric field on a disk?

An electric field on a disk refers to the distribution of electric charges on a circular surface. It is a vector field that describes the direction and strength of the electric force experienced by a charged particle at any point on the disk.

How is the electric field on a disk calculated?

The electric field on a disk can be calculated using Coulomb's law, which states that the electric field is directly proportional to the charge on the disk and inversely proportional to the square of the distance from the disk. It can also be calculated using Gauss's Law, which relates the electric field to the charge enclosed within the disk.

What are the factors that affect the electric field on a disk?

The electric field on a disk is affected by the charge distribution on the disk, the distance from the disk, and the size of the disk. It is also affected by the presence of other charged objects in the vicinity.

What is the direction of the electric field on a disk?

The direction of the electric field on a disk is perpendicular to the surface of the disk at every point. It points away from positively charged areas and towards negatively charged areas.

How does the electric field on a disk affect the motion of charged particles?

The electric field on a disk exerts a force on charged particles, causing them to accelerate in the direction of the field. The magnitude of the acceleration depends on the charge of the particle and the strength of the electric field.

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