A charge of -4.84 [tex] \mu C [/tex] is located at the origin, and a charge of -6.22 [tex] \mu C [/tex] is located along the y-axis at 1.361 m. The value of the Coulomb constant is 8.99 x 10^9. At what point along the y-axis is the electric field zero. Answer in units of m. I know that for the electric field to be zero, the electric field on the charges must equal each other. I called the distance from the charge at the origin R, and the distance from the second point is d-r. I used the equation for electric field and set them equal to each other. [tex] kQ/r^2= kq/(d-r)^2 [/tex] [tex] Q/r^2 = q/ (d-r)^2 [/tex] [tex] Q(d-r)^2 =qr^2 [/tex] [tex] (d-r)^2 =qr^2/ Q [/tex] [tex] (d^2 -2dr + r^2)/ r^2 = q/Q [/tex] [tex] d^2/r^2 - 2d/r +1 = q/Q [/tex] At this point I got stuck on how to solve for r, can someone help me? Thanks in advance.