Please help with the following problem:(adsbygoogle = window.adsbygoogle || []).push({});

A proton is placed between two oppositely charged plates, with a potential difference of 20.0 volts. if the distnace between the plates is 0.20 cm, calculate the following:

a. The ratio of the acceleration of the proton to an electron between the plates.

The electric field between the plates would have no charge because the charges of the plates would cancel each other out, right? So then it by itself would not produce any force correct? The proton which would have a positive charge would obviously be attracted to the negatively charged plate but how do I go about determining what force it produces?

b. The amount of work needed to move the proton halfway back across the potential to the negative plate.

Not even sure where to begin with this part of the problem

c. What potential difference would be needed to accelarate a proton from rest to a velocity of 0.30 the speed of light over a distance of 1.0 cm

I know the speed of light is = 3.0 x 10^8 so the velocity we want to attain would then be 9.0 x 10^7 but where do I go from there?

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# Homework Help: Electric Field Problem

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