Hi, Yesterday the professor was explaining an electric field problem. An electron with an initial velocity v0 is travelling to the right, and there's an electric field pointing up. The question was, what distance does the electron travel after 3s? After finding the acceleration due to the electric field, he showed us this: s(t) = v0(t) + (1/2)(a)t^2 and simply plugged in the values for v0 and a. But I was a bit confused. If v0 is to the right and a is downwards, doesn't that screw up the equation? I thought this equation only worked for calculating distance travelled in one dimension. What exactly is this distance - the distance travelled in x, y, the arclength of the electron's path, or what? Thanks for any help.