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penzoate
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Homework Statement
An electron with the kinetic energy of 2.6e-6 Joules is moving to the right along the axis of a cathode ray tube. the length of the cathode ray tube is 16 cm and the length of the deflection inside the cathode ray tube is 4 cm. The electric field = 2e4*N/C. Everywhere else the electric field is zero.
a:) how far is the electron from the axis of the tube when it reaches the end of the plates?
my solution:
Energy =.5*m*v^2 give the initial velocity.
(2*(2e-16 Joules)/(9.11e-31 kg))^.5=v
to find time, I used kinematic equation
x=x(0)+vt --> x-x(0)/v=t --> 16 m/v=t x isthe total length of the cathode ray tube
a=E*q/m(electron)
y=.5*a*t^2
not surehow to find x-component for the velocity, y or time t. Any other variables in this problems I should consider?