# Electric Field question

1. Jan 13, 2009

### accol

3. Here is my attempt:

First I figure I have to find the deceleration of the particle. So I plugged it into the v(final)^2= v(initial)^2 + 2ax. I solved for a and got a and got -240000.

I don't know if I am correct here but I plugged the accel and mass into F = ma and got a force of 1.608*10^-21N

I also tried substuting equations such as =

F = Eq

2. Jan 13, 2009

### gabbagabbahey

You have the right idea, but I get $a=-5.76 \times 10^{10} \text{m/s}^2$. Double check your calculation

3. Jan 13, 2009

### accol

Lol, wow.....and I thought I was doing it all wrong, I just put the wrong numbers into the calculator. Thanks

4. Jan 13, 2009

Welcome