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Electric field question

  1. Sep 29, 2009 #1

    Suy

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    1. The problem statement, all variables and given/known data
    the helium atom contains two protons in its nucleus. when helium is singly ionized, one of its two electrons is completely removed. the remaining electron orbits the nucleus at a radius of 2.65*10^-11
    a) what is the electric field strength created at the location of the electron by the nucleus?
    b)what is the electrostatic force acting on the electron?

    2. Relevant equations



    3. The attempt at a solution
    Just wondering , the question said the helium atom contains two protons, the charge of one proton is +1.60*10^-19, for a) do i multiply by 2? or the value 1.60*10^-19C stay the same?
     
  2. jcsd
  3. Sep 29, 2009 #2

    rl.bhat

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    Homework Helper

    Net charge in the nucleus is +2e, where e is the charge on the proton.
     
  4. Sep 29, 2009 #3

    Suy

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    is that mean I have to use the net charge for a)?
    ty
     
    Last edited: Sep 29, 2009
  5. Sep 29, 2009 #4

    rl.bhat

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    Yes.
     
  6. Sep 29, 2009 #5

    Suy

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    ok ty very much :)
     
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