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Electric field vs. Electric potential

  1. Jun 19, 2004 #1
    Hello everyone...I need help to start on a problem which states that V(r) =V(o) r^2/2R^2...I neeed to find E(r) when R and V(o) are constants...so from defention E= dV/Dr??? This is the part I am not sure how to move on..I have to integrate the equation they gave me keeping the V(o) and R as constants?
    Thank you...
     
  2. jcsd
  3. Jun 19, 2004 #2
    [tex]E = \frac{d}{dr}V(r)[/tex]

    V(r) is given, so you get

    [tex]E = \frac{d}{dr}\left(V_0 \frac{r^2}{2R^2} \right)[/tex]

    So what's the problem?

    cookiemonster
     
  4. Jun 19, 2004 #3
    The problem is that I have a very bad math backround...I am asking if I have to integrate that? Keeping V(o) and R outside the integral...I have not done integrals yet so I am having trouble with it...I have missed math (meaning didn't study it ) from basically 4th grade to 9th so to catch up on it takes me a while...
     
  5. Jun 19, 2004 #4
    E is defined as the derivative of V. You have V. You'd then have to differentiate V to get E.

    There are no integrals involved.

    Now, if you had E and you were asked to find V, then you'd have to integrate. But it's the other way around, hence differentiate.

    The problem is asking you to evaluate the derivative I described above.

    cookiemonster
     
  6. Jun 19, 2004 #5
    thank you :smile:
     
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