- #1
jg95ae
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I'm not sure if I've done this question correctly:
An equilateral triangle with sides of 15.6 cm, and a charge of +2 uC at one vertex, and charges if -4uC each at the other two. Determine the electric field at the centre of the triangle.
Basically what I've done is figure out the electric charge for each point, and then add them together. I'm not sure if this is even correct, and even if it is I'm not sure I understand why - I'm struggling a bit with the concepts.
E1 = kQ1/r^2 = (9 x 10^9)(0.002)/(0.156)^2 = 7.39 x 10^8 N/C
E2 = - 1.47 x 10^9 N/C
E3 = -1.47 x 10^9 N/c
Adding these three fields I got - 7.31 x 10^8 N/C as the electric field at the centre.
Thanks
An equilateral triangle with sides of 15.6 cm, and a charge of +2 uC at one vertex, and charges if -4uC each at the other two. Determine the electric field at the centre of the triangle.
Basically what I've done is figure out the electric charge for each point, and then add them together. I'm not sure if this is even correct, and even if it is I'm not sure I understand why - I'm struggling a bit with the concepts.
E1 = kQ1/r^2 = (9 x 10^9)(0.002)/(0.156)^2 = 7.39 x 10^8 N/C
E2 = - 1.47 x 10^9 N/C
E3 = -1.47 x 10^9 N/c
Adding these three fields I got - 7.31 x 10^8 N/C as the electric field at the centre.
Thanks