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Electric Field

  1. Feb 3, 2004 #1
    Here's the problem:
    A particle with a charge of 4.4nC is in a uniform electric field E directed to the left. It is released from rest and moves to the left. After it has moved 6.00 cm, its kinetic energy is found to be 3E-6 Joules.
    a) What work was done by the electric force?
    .000003 J
    b) What is the potential of the starting oint with respect to the endpoint?
    681.818 J
    I got these parts correct, but am having trouble with part c.
    c) What is the magnitude of E?

    Could someone give me a hint?? Thanks!!
  2. jcsd
  3. Feb 4, 2004 #2


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    Science Advisor

    That's 681 Volts, not Joules.
    Do you know that E=V/d for a uniform E-field where V is the potential difference across a distance d?
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