# Electric Field

1. Feb 19, 2007

### BunDa4Th

1. The problem statement, all variables and given/known data

If the electric field at a point in space has a magnitude of 300 volts/meter, about how far apart are the equipotential surfaces that differ by 10 volts?

well, i think that they are 30 meters apart. All I did was

300 volts/meter/10 volts since that will cancel the volts out i believe and leaving me with 300 meter/10 which give 30 meters.

I dont understand this question since my professor decided to skip this portion of the chapter and expect us to know it.

Any help on understanding would be great.

2. Feb 19, 2007

### Staff: Mentor

I think your answer and your intuition are correct. They certainly are for parallel plate capacitors. And I think they probably apply here for this spherical situation as well.

3. Feb 19, 2007

### hage567

4. Feb 19, 2007

### Saketh

EDIT: hage567 beat me to it.

5. Feb 19, 2007

### BunDa4Th

I just realize that. Now i have a problem on doing conversion with this. Can any of you guys give me some pointer on how to understand this since I quiet dont understand it.

I know there is this formula E = Kq/r^2 but I am not sure if that is what i have to use to figure this out.

I have also seek my lab TA for help on this and I still haven't even gotten a response and its been like 2 days.

Last edited: Feb 19, 2007
6. Feb 20, 2007

### BunDa4Th

Okay, i got some help but can anyone double check this to see if its the correct way,

10 volts/ 300vots/meter = .033 meter

7. Feb 20, 2007

### nrqed

Yes, that is right (assuming a uniform E field...that assumption is needed to answer the question). It's clear that this is correct since if the potential changes by 300 volts over a distance of 1.00 meter, it must take only 1.00 meter/30 to get a change of 10 volts.

8. Feb 20, 2007

### BunDa4Th

Sweet, thanks for checking it.

thanks to everyone who posted here.