- #1
Bert
- 28
- 0
Given is the electrical field [tex]&\mathbf{E}& = k[y^2 \^{&\mathbf{x}&} + (2xy + z^2)\^{&\mathbf{y}&} + 2yz \^{&\mathbf{z}&}][/tex]
I will like to find the potential so I integrate and become [tex]V(r) = -k (y^2x + xy^2 + z^2y + yz^2)[/tex] then I try to find the elektrical field again, so I differentiate this potential and become:
[tex] \frac{\partial v }{\partial x} =- k ( y^2 + y^2 )[/tex]
[tex]\frac{\partial v}{\partial y}=-k (2yx + 2xy + z^2 + z^2 )[/tex]
[tex]\frac{\partial v} {\partial z}=-k (2zy + 2yz) [/tex]
Wy find I two times the electrical field? and not ones? Thanks.
I will like to find the potential so I integrate and become [tex]V(r) = -k (y^2x + xy^2 + z^2y + yz^2)[/tex] then I try to find the elektrical field again, so I differentiate this potential and become:
[tex] \frac{\partial v }{\partial x} =- k ( y^2 + y^2 )[/tex]
[tex]\frac{\partial v}{\partial y}=-k (2yx + 2xy + z^2 + z^2 )[/tex]
[tex]\frac{\partial v} {\partial z}=-k (2zy + 2yz) [/tex]
Wy find I two times the electrical field? and not ones? Thanks.