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Electric field

  1. Jan 19, 2009 #1
    1. The problem statement, all variables and given/known data

    Find the electric field at position (2.00, 0)

    2. Relevant equations

    3. The attempt at a solution

    I am just confused by the question actually, does it mean at point 2 m to the right of 0,0? or is it to the left?

    The way I would solve this problem is by finding the electric field that each charges made 2 m from the point, for example the -.4nC, we can find the electric field at 2.00 by ke * -.4nC/2.5^2, and as well for the others and sum them all together, am I right?
  2. jcsd
  3. Jan 19, 2009 #2


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    Homework Helper

    Yes. The way I read the diagram, the 5nC is at the origin and they are asking for the point 1.2 m to the right of the 3nC charge.

    Yes. Superposition is right. The distances for each (left to right) to be clear would be 2.5, 2, 1.2 .
    Mind your signs.
  4. Jan 20, 2009 #3
    so basically it's just ke * -.4nC/2.5^2 + ke * 5nC/2^2 + ke * 3nC/1.2^2
  5. Jan 20, 2009 #4


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    That's what it looks like to me.
  6. Jan 20, 2009 #5
    What if the question now is (0, 2.00) instead of (2.00,0)?
  7. Jan 20, 2009 #6


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    That would mean apparently it was on the y axis. In which case get out your Pythagoras.
  8. Jan 20, 2009 #7
    I use the pythagorean theory to find the distance from the -4 and 3 charhea to the point (0, 2.00) only right?
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