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Electric field

  1. Oct 7, 2009 #1
    1. The problem statement, all variables and given/known data

    AN infinite plane in the xz plane carries a uniform surface charge density 65 nC/m^2. A second infinite plane carrying a uniform charge density 45 nC/m^2 intersect the xz plane at the z axis and makes an angle of 30 degree with the xz plane. Find the electric field in the xy plane at
    (a) x=6m, y=2m
    (b) x=6m, b=5m

    2. Relevant equations

    E=2*k*[tex]\pi[/tex]*[tex]\sigma[/tex]

    3. The attempt at a solution

    So the electric field due to the xz plane will be only in j direction (upward) so I just use the formula above to get the electric field.

    Then how can I move on with the electric field due to the remaining plane ? I don't really know what do I use the position for
     
  2. jcsd
  3. Oct 7, 2009 #2

    rl.bhat

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    Find E1 and E2 due to the two planes using relevant equation.
    in (a) tanθ = y/x = 2/6 = 1/3. So θ < 30 degrees. Hence point lies between the planes.
    In that situation what is angle between the electric fields?
    Similarly see what happens in (b).
     
  4. Oct 7, 2009 #3
    Will it be 150 degree ?
     
  5. Oct 7, 2009 #4

    rl.bhat

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    Yes.
     
  6. Oct 7, 2009 #5
    so do I use this 150 degree to calculate the component of the Electric field due to the 2nd plane ?

    The electric field due to the first plane is just in y direction (upward), right ?
     
  7. Oct 7, 2009 #6

    rl.bhat

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    Yes.
     
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