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StephenDoty
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Two 10cm-diameter charged disks face each other, 18 cm apart. Both disks are charged to - 30 nC. What is the electric field strength a point on the axis 5.0 cm from one disk between them?
[tex]\eta[/tex]/2[tex]\epsilon[/tex]0 * [1-1/[tex]\sqrt{1+ R^2/z^2}[/tex]]
with [tex]\eta[/tex] = -4.0 X 10^(-6) C/m^2
R=.05m z=.05cm for the left one and z=.13m for the right one
As I read this question, it is asking for the net electric field at a point .05m from one disk and .13m from the other. And since both disks are negative,the point will be attracted to both disks, making E1 and E2 opposite.
E1= -66190.6 N/C
E2= -15063.2 N/C
Both are negative meaning both are pointing towards their respective ring.
So to find Enet do I add E1 and E2? Making Enet= -81253.8 N/C = 81253.8 N/C toward the left ring??
Any help would be appreciated. Thanks.
Stephen
[tex]\eta[/tex]/2[tex]\epsilon[/tex]0 * [1-1/[tex]\sqrt{1+ R^2/z^2}[/tex]]
with [tex]\eta[/tex] = -4.0 X 10^(-6) C/m^2
R=.05m z=.05cm for the left one and z=.13m for the right one
As I read this question, it is asking for the net electric field at a point .05m from one disk and .13m from the other. And since both disks are negative,the point will be attracted to both disks, making E1 and E2 opposite.
E1= -66190.6 N/C
E2= -15063.2 N/C
Both are negative meaning both are pointing towards their respective ring.
So to find Enet do I add E1 and E2? Making Enet= -81253.8 N/C = 81253.8 N/C toward the left ring??
Any help would be appreciated. Thanks.
Stephen