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oooride
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I'm having trouble with this question. Where am I going wrong?
Three charges are at the corners of an equilateral trangle. The bottom left corner has a charge of 2.00e-6 C, bottom right -4.00e-6 C, and top with 7.00e-6 C and separated by 0.500m.
Calculate the electric field at the position of the 2.00e-6 C charge due to the 7.00e-6 C and -4.00e-6 C charges.
___________________________
E1 = [(K_e)(q1)(q2)/(r^2)]
=[-(8.99e9)(7.00e-6)(2.00e-6) / (.500m)^2] * [-cos(60)i - sin(60)j]
= 0.25172 i + 0.8660 j
___________________________
E2 = [(K_e)(q1)(q2)/(r^2)]
= [(8.99e9)(2.00e-6)(-4.00e-6) / (.500m)^2] * [cos(0)i]
= -0.28768 i
___________________________
(0.25172 i - 0.28768 i) = -0.03596 i
So, -0.03596 i and 0.8660 j
___________________________
I know this isn't right, where did I go wrong?
Any help is greatly appreciated
Thanks.
Three charges are at the corners of an equilateral trangle. The bottom left corner has a charge of 2.00e-6 C, bottom right -4.00e-6 C, and top with 7.00e-6 C and separated by 0.500m.
Calculate the electric field at the position of the 2.00e-6 C charge due to the 7.00e-6 C and -4.00e-6 C charges.
___________________________
E1 = [(K_e)(q1)(q2)/(r^2)]
=[-(8.99e9)(7.00e-6)(2.00e-6) / (.500m)^2] * [-cos(60)i - sin(60)j]
= 0.25172 i + 0.8660 j
___________________________
E2 = [(K_e)(q1)(q2)/(r^2)]
= [(8.99e9)(2.00e-6)(-4.00e-6) / (.500m)^2] * [cos(0)i]
= -0.28768 i
___________________________
(0.25172 i - 0.28768 i) = -0.03596 i
So, -0.03596 i and 0.8660 j
___________________________
I know this isn't right, where did I go wrong?
Any help is greatly appreciated
Thanks.
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