I'm having trouble with this question. Where am I going wrong?(adsbygoogle = window.adsbygoogle || []).push({});

Three charges are at the corners of an equilateral trangle. The bottom left corner has a charge of 2.00e-6 C, bottom right -4.00e-6 C, and top with 7.00e-6 C and separated by 0.500m.

Calculate the electric field at the position of the 2.00e-6 C charge due to the 7.00e-6 C and -4.00e-6 C charges.

___________________________

E1 = [(K_e)(q1)(q2)/(r^2)]

=[-(8.99e9)(7.00e-6)(2.00e-6) / (.500m)^2] * [-cos(60)i - sin(60)j]

= 0.25172 i + 0.8660 j

___________________________

E2 = [(K_e)(q1)(q2)/(r^2)]

= [(8.99e9)(2.00e-6)(-4.00e-6) / (.500m)^2] * [cos(0)i]

= -0.28768 i

___________________________

(0.25172 i - 0.28768 i) = -0.03596 i

So, -0.03596 i and 0.8660 j

___________________________

I know this isn't right, where did I go wrong?

Any help is greatly appreciated

Thanks.

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# Homework Help: Electric Fields charge problem

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