1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electric Fields & Force

  1. Mar 13, 2008 #1
    A small object carrying a charge of -5.50 nC is acted upon by a downward force of 24.0 nN when placed at a certain point in an electric field.

    What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?

    Magnitude & Direction of the Electric Field = 4.36 N/C upward

    F = k (Q1Q2/r^2)
    F = |q|E
    k = 9E9

    F = |q|E
    = 5.5E-9 x 4.36
    = 2.398E-8
  2. jcsd
  3. Mar 14, 2008 #2
    "Magnitude & Direction of the Electric Field = 4.36 N/C upward"

    I think this is correct so far, and then all you need to do is multiply the E by the charge of a proton.

    There is no need for k.

    I think u pretty much got it, maybe # error.
  4. Mar 14, 2008 #3

    Shooting Star

    User Avatar
    Homework Helper

    If you have found the field yourself, then what do you think should put in place of q?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Electric Fields & Force