1. Oct 26, 2007

### JFonseka

1. The problem statement, all variables and given/known data
Charge of a uniform density (8.0 nC/m2) is distributed over the entire xy plane. A charge of uniform density (5.0 nC/m2) is distributed over the parallel plane defined by z = 2.0 m. Determine the magnitude of the electric field for any point with z = 1.0 m.

2. Relevant equations

E = F/q

3. The attempt at a solution

Calculate the electric field at z = 1 due to the first plane, and then calculate the electric field at z = 1 due to the second plane. And then subtract the two?

I however don't know how to get the force, since the charge is given over a metre^2, what do I do?

2. Oct 26, 2007

### Astronuc

Staff Emeritus
3. Oct 26, 2007

### JFonseka

Ok I calculated the electric fields for the two planes. But those equations for calculating electric field don't have anything to do with the distance...

So if there is no distance in the equation how can the electric field be affected by distance.

4. Oct 26, 2007

### Astronuc

Staff Emeritus
5. Oct 26, 2007

### JFonseka

WHat do you mean 'between' the planes? The electric field for the first one will be higher because it's 8nC/m^2 than the second with 5nC/m^2 right?

I calculated the first one to have an electric field of 451.7N/C and the second to have 282.4
N/C

So i subtracted them and got 169N/C

That doesn't look right.

6. Oct 26, 2007

### JFonseka

Aha, hang on. The answer is 733N/C instead. So therefore I have to add them, why do I have to add them? They are pointing in the opposite directions aren't they? So one is positive and the other is negative. Hmm...

7. Oct 26, 2007

### JFonseka

Thanks for your help Astronuc! I will figure out the latter bit soon, but I understand this stuff better now.