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Electric Fields

  1. Apr 3, 2006 #1
    Here is the problem i am stuck on: There are 4 charges arranged in a rectangle pictured with side lengths .03m and .05m. The top 2 charges are negative and the bottom 2 charges are positive. All 4 charges have the same magnitude of 8.60*10^-12 C. Find the magnitude of the electric field at the center of the rectangle as pictured:

    1 2
    * *
    * *
    * *
    * *
    * *
    3 4

    So first i found the radius to each charge which is the same for all the charges. so the radius is the square root of (.015m^2+.025^2) = .0292 m
    So i know that E1=E2=E3=E4 since the radius is the same for all the charges. So E=kq/(r^2)=8.99*10^9(8.6*10^-12)/(.029^2)=91.9. The Electric field is doubled though for the top 2 charges because the positive electric field points away from itself and the negative electric field points toward itself so i know that this combined electric field is 2*91.9 = 184. I know this is right because i got this part of the question right. Now to find the electric field at the center of the rectangle, i would think to use the pythagorean theorom and say Enet= square root of (184^2+184^2)= 260. However, the CPU tells me this is wrong. Please help me out. Thanks.
  2. jcsd
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