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Electric fields

  1. Jan 17, 2008 #1
    1. The problem statement, all variables and given/known data

    An electron moving to the right at 3% the speed of light enters a uniform electric field parallel to its direction of motion. The electron is to be brought to rest in the space of 6.0cm.
    What is the strength of the field?______N/C

    2. Relevant equations

    F = q * E

    3. The attempt at a solution

    Speed = .03 * 3*10^8 = 9,000,000
    distance = 6cm = .06m

    F = .06 * 9,000,000 = 5.4*10^5 = 5.4*10^2 N/C
     
  2. jcsd
  3. Jan 17, 2008 #2

    rl.bhat

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    While calculating the field you have not taken into account the charge and mass of the electron. Here you have to take the relativistic mass.
     
  4. Jan 17, 2008 #3
    And that would be 50 * 10^-6 ?
     
  5. Jan 17, 2008 #4

    rl.bhat

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    And that would be 50 * 10^-6 ?
    From where did you get this number? What is this?
     
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