- #1

- 1

- 0

Gauss' Law states that flux=Eda=4(pi)kq for any closed surface

Since I have dipoles, my electric fields will be pulled toward the negative charge. THerefore, surfaces with negative charges in them should have a negative flux b/c the field points to the interior of the closed surface while my surfaces encompassing positive charges should have positive flux b/c the field points to the exterior of the surface. So, since each surface has a flux of 4pikq wouldn't the flux just keep adding up as the vector went through each additional surface?

thanks