Electric flux through a cube

  • Thread starter Oblivion77
  • Start date
  • #1
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Homework Statement


33nc4g7.png

20zp4s3.png



Homework Equations



E * A

The Attempt at a Solution



I need to find the electric flux through each face. I am a bit confused. I believe the flux through sides 3 and 1 are zero because those sides are parallel to the electric field. The whole flux through the cube should be 0, I am not sure how to find the electric flux through the other sides because the electric field has 2 components.
 
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Answers and Replies

  • #3
113
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Would the angle be Tan(3.27/5.20) for the electric field?
 
  • #4
113
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Ok, if I start to write out the area vectors I get.

A1 = -L[tex]^{2}[/tex]j
A2 = L[tex]^{2}[/tex]k
A3 = L[tex]^{2}[/tex]j
A4 = -L[tex]^{2}[/tex]k
A5 = L[tex]^{2}[/tex]i
A6 = -L[tex]^{2}[/tex]i

Now I need to multiple these by the electric field, what is the best way to do it?
 
  • #6
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Use the definition of flux. It is the dot product of the electric field and the outwardly directed area vector. Since the electric field is non-uniform, you will need to do a little calculus. You should notice that the x-coordinate is constant on two faces, and the z-coordinate is constant on two faces.
 
  • #7
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I am still confused, I haven't really done a problem before with a non-uniform electric field. My textbook doesn't really have any good examples of this.
 
  • #8
113
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Ahhh, I think I understand it now.
 

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