Electric Flux and Charge Distribution in a Cube with Uniform Electric Fields

In summary, a single point charge would not be able to produce a uniform electric field over a flat surface.
  • #1
Bashyboy
1,421
5

Homework Statement


Hello, the problem I am working on is:

Assume the magnitude of the electric field on each face of the cube of edge L = 1.05 m in the figure below is uniform and the directions of the fields on each face are as indicated. (Take E1 = 31.5 N/C and E2 = 26.5 N/C.)

(a) Find the net electric flux through the cube.

(b) Find the net charge inside the cube.

(c) Could the net charge be a single point charge?

I attached the diagram in my post.


Homework Equations





The Attempt at a Solution


I was able to answer all but part (c) properly. I answered yes. Is it false because there aren't any electric field lines flowing out from the cube through one of the surfaces?
 

Attachments

  • Capture.JPG
    Capture.JPG
    9.2 KB · Views: 2,333
Physics news on Phys.org
  • #2
The electric field is given to be uniform over each face. Can you think of any way that a single point charge could produce a uniform field over a flat surface?
 
  • #3
Well, if the point charge was placed at the geometric center, wouldn't the same amount of electric field lines emanating from the point charge go through each face?
 
  • #4
Bashyboy said:
Well, if the point charge was placed at the geometric center, wouldn't the same amount of electric field lines emanating from the point charge go through each face?

Yes, the flux would be the same for each face. But I don't see how that helps. For your problem, the flux is not the same through each face.

In your problem, each face has an electric field that is perpendicular to the face and has constant magnitude over the face. Can this be achieved with a single point charge inside?

Actually, you would be allowed to set up any charges anywhere outside the cube without affecting the net charge inside. So, the question is whether or not you could arrange charges outside the cube along with a single point charge inside to produce the given uniform fields at each face of the cube.
 
  • #5
Oh, I see. If it were a point contained at the geometric center, there would be more than one electric field line passing through each face, and some of them would be at an angle less than 90 deg., relative to the face that that electric field line is passing through. Is that correct?
 
  • #6
Bashyboy said:
Oh, I see. If it were a point contained at the geometric center, there would be more than one electric field line passing through each face, and some of them would be at an angle less than 90 deg., relative to the face that that electric field line is passing through. Is that correct?

That's right. The field of a point charge could not be perpendicular to to a flat surface at each point of the surface.
 
  • #7
Why can't there be exactly one electric field line on each face that is perpendicular to it? I know the rest of the electric field lines will be at different angles, but it seems like at least one would be.
 
  • #8
The picture that you posted is just indicating the direction of the electric field at each face. It does not mean that there is only one electric field line for each face. If you were to draw the electric field lines at the left face, for instance, then you would draw a number of parallel field lines equally spaced and perpendicular to the face.
 
  • #9
TSny said:
The picture that you posted is just indicating the direction of the electric field at each face. It does not mean that there is only one electric field line for each face. If you were to draw the electric field lines at the left face, for instance, then you would draw a number of parallel field lines equally spaced and perpendicular to the face.

No, I understand this. I was just supposing the situation where we had a point charge, instead of the charge distribution in the problem--whatever that may be. So, if there was actually a point charge in it, why isn't it true that at least one electric field line is perpendicular to each face?
 
  • #10
In that case, you're right. Each face would have one electric field line from the point charge that would be perpendicular to the face.
 
  • #11
Wow, this seems too incredible: me, correct for a change. Thank you very much, TSny.
 

1. What is electric flux through a cube?

Electric flux through a cube is a measure of the electric field passing through the cube. It is a scalar quantity defined as the dot product of the electric field and the area of the cube's surface.

2. How is electric flux through a cube calculated?

The electric flux through a cube can be calculated by multiplying the magnitude of the electric field by the surface area of the cube that is perpendicular to the electric field. This can be represented mathematically as Φ = E * A * cos(θ), where Φ is the electric flux, E is the electric field, A is the area, and θ is the angle between the electric field and the normal vector of the surface.

3. What is the unit of electric flux through a cube?

The unit of electric flux through a cube is volt-meters (V*m) or newton-meters squared per coulomb (N*m^2/C). This unit is equivalent to the unit of electric field, which is volts per meter (V/m).

4. How is electric flux through a cube affected by the orientation of the cube?

The electric flux through a cube is affected by the orientation of the cube in relation to the electric field. If the cube is perpendicular to the electric field, the electric flux will be at its maximum value. However, if the cube is parallel to the electric field, the electric flux will be zero. The electric flux will also be affected by the angle between the electric field and the normal vector of the cube's surface.

5. What is the significance of electric flux through a cube?

The electric flux through a cube is an important quantity in understanding the behavior of electric fields. It can help determine the amount of electric field passing through a given surface, which can be useful in many applications such as designing electrical circuits or studying the behavior of charged particles. Additionally, it is a key concept in Gauss's law, which relates the electric flux through a closed surface to the charge enclosed within that surface.

Similar threads

  • Introductory Physics Homework Help
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
891
  • Introductory Physics Homework Help
Replies
1
Views
5K
Replies
17
Views
979
  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Introductory Physics Homework Help
Replies
17
Views
6K
Back
Top