Electric Flux Through a Uniform Electric Field

[musicman05]

You have a uniform electric field described by the vector (4 i + 2 j + 13 k)N/C and a flat surface describe by the vector (5 i + 9 j - 2 k)m2. What is the electric flux through this surface?

 

[Hootenanny]

You have a uniform electric field described by the vector (4 i + 2 j + 13 k)N/C and a flat surface describe by the vector (5 i + 9 j - 2 k)m2. What is the electric flux through this surface?

The vector describing a surface is usually normal to the surface. What is the definition of the flux of a vector field?

 

[Moetasim]

The electric flux through a surface is a measure of the amount of electric field passing through the surface. In this case, we have a uniform electric field described by the vector (4 i + 2 j + 13 k)N/C and a flat surface described by the vector (5 i + 9 j - 2 k)m2. To determine the electric flux through this surface, we can use the formula:

Electric flux = E * A * cos(theta)

Where E is the electric field, A is the area of the surface, and theta is the angle between the electric field and the surface. In this case, we can calculate the electric flux as follows:

Electric flux = (4 i + 2 j + 13 k)N/C * (5 i + 9 j - 2 k)m2 * cos(theta)

Since the electric field and the surface are perpendicular to each other, the angle between them is 90 degrees and the cosine of 90 degrees is 0. Therefore, the electric flux through this surface is 0. This means that there is no net electric field passing through the surface, as the surface is parallel to the electric field lines.