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I don't understand the part about cos[tex]\theta[/tex].....

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- Thread starter yaik
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- #1

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I don't understand the part about cos[tex]\theta[/tex].....

- #2

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It came from the dot product between E and dA, i.e. the projection of E along the differential area.

You may want to bookmark the entire Hyperphysics website.

Zz.

- #3

tiny-tim

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Hi yaik! Welcome to PF!

Imagine you want to know the flux of bugs flying horizontally along a road.

If you count the number that go splat on your windscreen, then you'll collect less (in a given time) if the windscreen is tilted: the number will be greatest at 90º, and zero at 0º: it'll be proportional to cosθ.

Mathematically, flux of a field **E** through a surface with area A is **E**.(A**ñ**), where **ñ** is the unit vector normal (perpendicular) to the surface.

- #4

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thx!!!

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