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Electric Force and Field

  • Thread starter Ezhil
  • Start date
  • #1
4
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Hi
I was just doing my homework and i am stuck on this question. Can you please help me with this?

a) Caluculate the electric field strength E, at a point located 3.0 cm due east from a point charge q=+1.0 microcoulomb.

I know i have to use the formulas:
E = F/q

And Coulomb's law. But to use Coulomb's law you need to two charges and this question only has one. Please help on this, Thankyou.

Ezhil
 

Answers and Replies

  • #2
Tide
Science Advisor
Homework Helper
3,076
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If the force on q due to Q is
[tex]\vec F = qQ \frac {\vec r}{r^3}[/tex]
then the electric field due to Q is
[tex]\vec E = Q \frac {\vec r}{r^3}[/tex]
 
  • #3
4
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Am i right in saying:
E = (k*Qsource) / (r^2)

therefore
E=[(9*10^9)*(1.0*10^-6)] / (0.03)^2
E= 1.0*10^7
 
  • #4
4
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[tex]\vec E = Q \frac {\vec r}{r^3}[/tex]

What is the vector r equal to and is the Q the point charge 1.0 microcoulomb that is given in the problem?
I'm sorry i don't understand the equation completly, im still in year 11.
 
  • #5
Tide
Science Advisor
Homework Helper
3,076
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[itex]\vec r[/itex] is the displacement vector from charge Q to charge q.
 
  • #6
4
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Thank you for your help!
 

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