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Electric Force and Field

  1. Sep 27, 2004 #1
    Hi
    I was just doing my homework and i am stuck on this question. Can you please help me with this?

    a) Caluculate the electric field strength E, at a point located 3.0 cm due east from a point charge q=+1.0 microcoulomb.

    I know i have to use the formulas:
    E = F/q

    And Coulomb's law. But to use Coulomb's law you need to two charges and this question only has one. Please help on this, Thankyou.

    Ezhil
     
  2. jcsd
  3. Sep 27, 2004 #2

    Tide

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    If the force on q due to Q is
    [tex]\vec F = qQ \frac {\vec r}{r^3}[/tex]
    then the electric field due to Q is
    [tex]\vec E = Q \frac {\vec r}{r^3}[/tex]
     
  4. Sep 27, 2004 #3
    Am i right in saying:
    E = (k*Qsource) / (r^2)

    therefore
    E=[(9*10^9)*(1.0*10^-6)] / (0.03)^2
    E= 1.0*10^7
     
  5. Sep 27, 2004 #4
    [tex]\vec E = Q \frac {\vec r}{r^3}[/tex]

    What is the vector r equal to and is the Q the point charge 1.0 microcoulomb that is given in the problem?
    I'm sorry i don't understand the equation completly, im still in year 11.
     
  6. Sep 27, 2004 #5

    Tide

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    [itex]\vec r[/itex] is the displacement vector from charge Q to charge q.
     
  7. Oct 6, 2004 #6
    Thank you for your help!
     
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