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Electric Force Equilibrium

  1. Sep 6, 2012 #1
    1. The problem statement, all variables and given/known data
    Two identical conducting small spheres are placed with their centers .300 m apart. One is given a charge of 12.0 nC and the other is given a charge of -18.0nC. a) Find the electric foce exterted on one sphere by the other. B) the sphers are connected by a conducing wire. Find the electric force between the two after they have come to equilibrium.



    2. Relevant equations
    F=(((q1)(q2))/r^2)(8.99 x 10^9 N M^2/c^2)



    3. The attempt at a solution
    I used the above equation to calculate the charge to be -2.1576 x 10^5 N. for problem A. For B, I am curious if i'm simplyfying to much, but since there is equilibrium would the resulting charge be zero?

    Thank you for the help!
     
  2. jcsd
  3. Sep 6, 2012 #2
    The resultant charge is the sum of the original charges. What is it?
     
  4. Sep 6, 2012 #3
    -6.0 nC because there is still a disproportionate number of electrons within the system? Is it found by adding the two forces together?
     
    Last edited: Sep 6, 2012
  5. Sep 6, 2012 #4
    It's -6.0 nC because one sphere had +12 and the other had -18. The total charge of the system must be conserved.

    You need to figure out how this charge is divided between the two spheres, though.
     
  6. Sep 6, 2012 #5
    Is it an even -3.0nC charge in each sphere because the spheres and the connecting wire are both conductive so the electrons are equally spaced?

    Then using the -3.0nC in the original formula as both q1 and q2 to calculate the new repulsive force?
     
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