# Electric Force Equilibrium

SIUnitConvert

## Homework Statement

Two identical conducting small spheres are placed with their centers .300 m apart. One is given a charge of 12.0 nC and the other is given a charge of -18.0nC. a) Find the electric foce exterted on one sphere by the other. B) the sphers are connected by a conducing wire. Find the electric force between the two after they have come to equilibrium.

## Homework Equations

F=(((q1)(q2))/r^2)(8.99 x 10^9 N M^2/c^2)

## The Attempt at a Solution

I used the above equation to calculate the charge to be -2.1576 x 10^5 N. for problem A. For B, I am curious if I'm simplyfying to much, but since there is equilibrium would the resulting charge be zero?

Thank you for the help!

voko
The resultant charge is the sum of the original charges. What is it?

SIUnitConvert
-6.0 nC because there is still a disproportionate number of electrons within the system? Is it found by adding the two forces together?

Last edited:
Muphrid
It's -6.0 nC because one sphere had +12 and the other had -18. The total charge of the system must be conserved.

You need to figure out how this charge is divided between the two spheres, though.

SIUnitConvert
Is it an even -3.0nC charge in each sphere because the spheres and the connecting wire are both conductive so the electrons are equally spaced?

Then using the -3.0nC in the original formula as both q1 and q2 to calculate the new repulsive force?