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Electric force on the charge kept at the centre of a metallic shell
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[QUOTE="Pushoam, post: 6851222, member: 619344"] The above charge distribution doesn't guarantee 0 electric field inside the meat of the shell. The inner surface of a conducting shell has to be equipotential. In the given diagram, potential near the negative charge is not equal to the potential near the positive charge. Besides this charge distribution also creates a component of electric field along the inner surface. The charges will move on the inner surface to make it equipotential and 0 electric field. Just because the diagram satisfies the Gauss's law doesn't mean that electric field inside the meat is 0. To cancel the field due to ##q_1## in the meat of the shell, a part of charge Q distributes on the upper surface and rest of Q on the inner surface. So, the negative charge can not stay there on its own. It gets neutralised due to the presence of other positive charge. [/QUOTE]
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Electric force on the charge kept at the centre of a metallic shell
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