1. The problem statement, all variables and given/known data Consider the circuit in the figure below, in which C2 = 16 µF and V = 80 V. Initially, the switch in is in position A and capacitors C2 and C3 are uncharged. Then the switch is flipped to position B. Afterward, what are the charge on and the potential difference across each capacitor? http://www.webassign.net/knight/p30-70alt.gif 2. Relevant equations Q= C * delta V where C is the capacitance in farads and Q is the charge on each capacitor plate (the charge on one plate is equal and opposite the charge on the other) Equivalent capacitance of capacitors in series: (1/C1 + 1/C2)^-1 Equivalent capacitance of capacitors in parallel: C1 + C2 3. The attempt at a solution I figured that the capacitors in series should have the same charge, so Q2=Q3. I also figured that the first capacitor should have the same potential difference as the other two capacitors put together, or deltaV1= deltaV2+deltaV3. I finally figured that the sum of the final charges on all the capacitors should equal the initial charge, which I found to be Qi= C1deltaVi = 15 microfarads * 80 V= 0.0012 C. Is this all right? If it is, even with these equations I haven't been able to solve this problem. I've tried endless rearrangements of the equations above and I always still have a variable I don't know. I don't know if it will come into play, but I solved for the equivalent capacitance of C2 and C3 and got 10.438 microfarads. Please give me a detailed answer if you can. I'd appreciate any help, but really short answers are probably not going to help me at this point, given that I've already spent over two hours on this problem!