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I have a question on electric potential, potential energy and work.

##\Delta V = \frac{\Delta U}{q_o}##

##W = q_o\Delta V##

##W = -\Delta U##

Example:

A point A that is closer to the source charge than point B, then the electric potential difference is negative (##\Delta V = V_B - V_A##)

When we now have a negative test charge that moves from A to B. If a negative test charge is moved through a negative potential difference, the potential energy is positive. But then that means that the work is both positive and negative given the two equations above. Can someone explain the problem here?