1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electric potential concepts

  1. Feb 14, 2009 #1
    I need some help on those multiple choice questions that I'm using to learn the concepts. Some of them I know how to do and needs someone to check my work. Other ones I need hints so I know how to start.

    04e36.jpg

    1. Three ½ μF capacitors are connected in series as shown in the diagram above. The capacitance of the combination is
    (A) 3/2 μF
    (B) 1 μF
    (C) 2/3 μF
    (D) 1/2 μF
    (E) 1/6 μF

    I used this equation: 1/Ceq = 1/C1 + 1/C2 + 1/C3 and got E as the answer.


    2. In a certain region, the electric field along the x-axis is given by

    E = ax + b, where a = 40 V/m2
    and b = 4 V/m.

    The potential difference between the origin and x = 0.5 m is
    (A) -36 V
    (B) -7 V
    (C) -3 V
    (D) 10 V
    (E) 16 V


    I tried to plug in 0 and 0.5 for x and subtract them but that didn't work out.


    3. A 20 μF parallel-plate capacitor is fully charged to 30 V. The energy stored in the capacitor is most nearly
    (A) 9x103 J
    (B) 9xl0-3 J
    (C) 6x10-4 J
    (D) 2x10-4 J
    (E) 2x10-7 J

    Used the equation U = (1/2)CV2 and got B as the answer.


    4. A potential difference V is maintained between two large, parallel conducting plates. An electron starts from rest on the surface of one plate and accelerates toward the other. Its speed as it reaches the second plate is proportional to
    (A) 1/V
    (B) 1 / √V
    (C) √V
    (D) V
    (E) V2

    qV = (1/2)mv2

    When I rearrange it to isolate v it's proportional to √V so it's C.

    04e48.jpg

    5. A solid metallic sphere of radius R has charge Q uniformly distributed on its outer surface. A graph of electric potential V as a function of position r is shown above. Which of the following graphs best represents the magnitude of the electric field E as a function of position r for this sphere?

    04e49.jpg

    Electric field in a conductor is 0 and is proportional to 1/r2, so C is the answer.

    04e59.jpg
    This diagram is used for the next 3.

    6. Which vector below best describes the direction of the electric field at point A?

    04e59a.jpg

    Electric field directs toward lower potential, so it's D???

    7. At which point does the electric field have the greatest magnitude?

    (A) A
    (B) B
    (C) C
    (D) D
    (E) E

    Not sure. How do I start?

    8. How much net work must be done by an external force to move a -1 μC point charge from rest at point C to rest at point E?

    (A) -20 μJ
    (B) -10 μJ
    (C) 10 μJ
    (D) 20 μJ
    (E) 30 μJ

    W = qV
    = -1(20 - 10)
    = -10 μJ

    It's B.



    Can someone(s) also please explain to me when is work done by field positive or negative? Thanks.
     
  2. jcsd
  3. Feb 14, 2009 #2

    Delphi51

    User Avatar
    Homework Helper

    E = dV/dx. So in #2 to get the V you must integrate Edx.
    In #6, wouldn't it be A that points toward the lower V - perpendicular to the V line?
    In #7, you want the place where the lines of constant potential are closest together so the dV/dx is highest.
     
  4. Feb 14, 2009 #3
    So you mean that in #7 B is the correct answer since the potential lines are the closest?
     
  5. Feb 14, 2009 #4

    Delphi51

    User Avatar
    Homework Helper

  6. Feb 15, 2009 #5
    How do I do #2?
     
  7. Feb 15, 2009 #6

    Delphi51

    User Avatar
    Homework Helper

    in #2 to get the V you must integrate Edx.
    Use the expression you have for E and perform the integration.
    If you have trouble, show your work here so we can see what is going on.
     
  8. Feb 15, 2009 #7
    Ok, I see.

    V = −∫E∙dr
    = −ax2/2 + bx
    = −20x2 − 4x

    When x = 0.5
    V = −7, so B is the answer.

    Is this correct?
     
  9. Feb 15, 2009 #8

    Delphi51

    User Avatar
    Homework Helper

    Yes, that's what I get.
     
  10. Feb 15, 2009 #9
    Thank you for your help.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Electric potential concepts
Loading...