Hello,(adsbygoogle = window.adsbygoogle || []).push({});

The electric potential is defined as:

$$

\phi(\vec{r}) = \int d^3r' \frac{\rho(\vec{r}')}{|\vec{r} - \vec{r}'|}.

$$

My question is, for solving for the potential inside of a charged solid sphere (constant charge density) by using the above equation I get,

$$

\frac{Q}{2R} \bigg( \frac{r^2}{R^2} - 3 \bigg).

$$

When the result is actually the above multiplied by a minus sign. Is this because when we take the reference point to be infinity, that we apply a minus sign by convention?

I just want to be sure exactly why the minus sign is introduced.

**Physics Forums - The Fusion of Science and Community**

# Electric potential convention

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Electric potential convention

Loading...

**Physics Forums - The Fusion of Science and Community**