A proton is fired from far away toward the nucleus of a mercury atom. Mercury is element number 80, and the diameter of the nucleus is 14.0 fm. If the proton is fired at a speed of 4.0 times 10^7, what is its closest approach to the surface of the nucleus? Assume the nucleus doesn't move
The Attempt at a Solution
I really don't know how to start this problem if anyone could give me some advice on how to approach it Id appriciate it.