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Electric potential inside a shell of charge
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[QUOTE="rude man, post: 6001951, member: 350494"] Or perhaps:In Q2: the E field just outside the surface is σ/ε where σ is surface charge density (related to λ obviously). The E field just below the surface is zero. Both by Gauss. Since potential is the integral of the E field over distance, and the distance → zero, therefore there is no change in potential between the outside & inside surfaces. Q1: Can also do this by superposition theorem: Potential of shell 1 with q2=0 is kq1/R1. Potential of shell 2 with q1=0 is kq2/R2. Total potential is sum of above potentials. [/QUOTE]
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Electric potential inside a shell of charge
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