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**1. Homework Statement**

An electric field is given by E = 2xî - 3y²j N/C. Find the change in potential from the position RA = î - 2j M to RB = 2î + j +3k m.

**2. Homework Equations**

∆V = VA - VB = - ∫

**E**• d

**s**

*(definite integral from A to B)*

*Or in a uniform field, simply:*

∆V = VA - VB = ±Ed

**3. The Attempt at a Solution**

I know from the solutions manual that the answer is +6 Volts.

I began by finding ∆R = RB - RA = i + 3j + 3k m.

That can easily be converted into ∆R = √19 right?

My problem comes in when I have to deal with E = 2xî - 3y²j N/C.... what do I do with the square on the y?

Thank you once again.