An electric field is given by E = 2xî - 3y²j N/C. Find the change in potential from the position RA = î - 2j M to RB = 2î + j +3k m.
∆V = VA - VB = - ∫ E • ds (definite integral from A to B)
Or in a uniform field, simply:
∆V = VA - VB = ±Ed
The Attempt at a Solution
I know from the solutions manual that the answer is +6 Volts.
I began by finding ∆R = RB - RA = i + 3j + 3k m.
That can easily be converted into ∆R = √19 right?
My problem comes in when I have to deal with E = 2xî - 3y²j N/C.... what do I do with the square on the y?
Thank you once again.