1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electric strength problem

  1. Feb 24, 2004 #1
    https://hw.utexas.edu/tmp/Muddam1/1077653690Xuj.pdf [Broken]

    I did this: I manipulated [tex]E = \frac{q}{\epsilon*A}[/tex] to get [tex]q = E*\epsilon*A[/tex] (E= electric strength), so 1.6e7*8.85e-12*.0246*.0501 = 1.74516e-7 but because the HW asks the answer to the 1e-6, I divided 1.74516e-7/1e-6= .174516 but it's wrong does anyone know why?
    Last edited by a moderator: May 1, 2017
  2. jcsd
  3. Feb 24, 2004 #2
    Your link does not work.
  4. Feb 24, 2004 #3

    Ok this is the problem

    009 (part 1 of 2) 10 points
    A parallel-plate capacitor of dimensions
    2:46 cm £ 5:01 cm is separated by a 0:61 mm
    thickness of paper.
    Find the capacitance of this device. The
    dielectric constant · for paper is 3.7. Answer
    in units of pF.

    I got this right.

    010 (part 2 of 2) 10 points
    What is the maximum charge that can be
    placed on the capacitor? The electric strength
    of paper is 1:6 £ 107 V=m. Answer in units of 1e-6c.
    this is the one I need help on
  5. Feb 24, 2004 #4

    Never mind, I got it.
  6. Feb 24, 2004 #5
    So what's the answer?
  7. Feb 24, 2004 #6
    I used a different formula to get the answer: [tex]q = E*k\epsilon*A[/tex]
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook