Electric Trains (in general)

  • #1
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Hi

I thought I remember reading that transmitting power over 800km's is passed the break even point for DC vs AC. And I read that modern rail is starting to use 25KV AC, but aren't many networks bigger than that, specifically in NSW Australia, the according to wikipedia it's 815km, I'm not sure if that is from top to toe, I assume it is. So wouldn't it actually be more efficient to have it as DC? From a transmission perspective.

Side point: [The benefit of transmitting HV is less current needed for necessary power. I know that the power loss of transmitting is in the I^2 term, which is of importance, there is also parasitic inductance for AC transmission. But side point, I know the electrons in AC just sitting there oscillating, and the slow but present electron drift of DC doesn't effect this does it? Like adding to the the current in power losses? I'd have thought the mode of AC or DC wouldn't effect the loss in I^2.]

I am aware that series DC motors are great because of the torque characteristic.
In the old days, couldn't they still use a wound rotor induction motor, just just vary the resistance of the rotor to get maximum torque on start up? And so use AC?

Now that we can control the frequency easily with solid-state technology, is the switch to AC trains just based on the fact that induction motors are really robust and you don't need to replace commutators all the time?

Thanks
 

Answers and Replies

  • #2
davenn
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I thought I remember reading that transmitting power over 800km's is passed the break even point for DC vs AC. And I read that modern rail is starting to use 25KV AC, but aren't many networks bigger than that, specifically in NSW Australia, the according to wikipedia it's 815km, I'm not sure if that is from top to toe, I assume it is. So wouldn't it actually be more efficient to have it as DC? From a transmission perspective.
There is no single full length of 815 km. That distance covers ALL the small side lines etc
the electrified part of the network doesn't stretch too far beyond Sydney.
1) the north line from Sydney to Newcastle is around 120km
2) the west line from Sydney to Lithgow is around 115 km
3) the south line from Sydney to Kiama is around 100km

And I read that modern rail is starting to use 25KV AC,
back in the 1990's there were plans to electrify the Newcastle to ~ Muswellbrook ( ie up through the Hunter Valley) using 25kVAC but the plans were abandoned

... but don't forget there can be multiple power feeds into the system along its length that negate the problem you assumed existed


Dave
 
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  • #3
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the electrons in AC are indeed drifting back and forth but they themselves don't add to the "current in power loss" as you say , current is current there isn't anything that adds to it or takes away from it , if you have a given length of wire with resistance X , and you apply a potential to it's both ends, you have a current through that wire , which is directly proportional to the applied voltage.This is by Ohms law.
I=V/R

from reading your post I got the feeling you are asking whether DC has no ohmic loss over a length of wire is that correct?
If that is what you thought , it is wrong.
The only reason at long distance DC is preferred over AC is because AC has additional inductive loss also higher capacitive losses , also DC has fewer conductors necessary.But it's distribution is much more complicated.
 
  • #4
davenn
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The only reason at long distance DC is preferred over AC is because AC has additional inductive loss also higher capacitive losses , also DC has fewer conductors necessary.But it's distribution is much more complicated.
going by that response ... I'm not sure if you actually realise the topic of the discussion ?


D
 
  • #5
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There is no single full length of 815 km. That distance covers ALL the small side lines etc
the electrified part of the network doesn't stretch too far beyond Sydney.
1) the north line from Sydney to Newcastle is around 120km
2) the west line from Sydney to Lithgow is around 115 km
3) the south line from Sydney to Kiama is around 100km



back in the 1990's there were plans to electrify the Newcastle to ~ Muswellbrook ( ie up through the Hunter Valley) using 25kVAC but the plans were abandoned

... but don't forget there can be multiple power feeds into the system along its length that negate the problem you assumed existed


Dave
Ah, interesting figures, now that I see them it seems obvious. But what "problem I assumed existed" is negated by multiple power feeds? About my question as to why no AC over DC? Because I thought the issue may have been commutators:
I am aware that series DC motors are great because of the torque characteristic.
In the old days, couldn't they still use a wound rotor induction motor, just just vary the resistance of the rotor to get maximum torque on start up? And so use AC induction motors instead?

Now that we can control the frequency easily with solid-state technology, is the switch to AC trains just based on the fact that induction motors are really robust and you don't need to replace commutators all the time?
But playing devils advocate, if there was a long electrified line over 800kms (which probably would be very rare) would it not be more economical to have it DC because it's past the 'break even point' with AC?


the electrons in AC are indeed drifting back and forth but they themselves don't add to the "current in power loss" as you say , current is current there isn't anything that adds to it or takes away from it , if you have a given length of wire with resistance X , and you apply a potential to it's both ends, you have a current through that wire , which is directly proportional to the applied voltage.This is by Ohms law.
I=V/R

from reading your post I got the feeling you are asking whether DC has no ohmic loss over a length of wire is that correct?
If that is what you thought , it is wrong.
The only reason at long distance DC is preferred over AC is because AC has additional inductive loss also higher capacitive losses , also DC has fewer conductors necessary.But it's distribution is much more complicated.
Sort of, not really what I meant.
I haven't done any electrical theory in over 7 months, but then last night on researching this topic I was thinking about AC current, and how weird a concept that is. Even though we say there is a current traveling from ac generation source to load, or for that matter from fault back to neutral. (I've done Electric Systems, and there was a significant +,- & zero sequence component of fault studies in Power And Machiens) So I took it for granted that there actually is an AC current, but I can't imagine there actually being, if the drift velocity of an electron is 8cm an hour and they're oscillating at 50Hz, then they're not going anywhere. As I envision it in a copper wire the electrons in a wire stop the electric field from leaving out the sides, and allow the electric field to be transmitted.
So I know that there are inductive losses from long distance over head power transmission, and if I'm running a large motor from the supply that is generated miles away then that current that the AC motor draws is going to add to the I^2.R losses of the transmission line, I'm just trying to understand how if the electrons aren't really moving, also I'm trying to compare that to an equivalent DC I^2.R loss where the electrons in the transmission line do actually move.
The only thing I can conjure to explain this is that the electrons are actually moving very fast, because If I'm running an inverter then surely electrons are actually jumping over the junctions very fast.

thanks very much!
 
  • #6
davenn
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But playing devils advocate, if there was a long electrified line over 800kms (which probably would be very rare) would it not be more economical to have it DC because it's past the 'break even point' with AC?
read my comment again you seemed to miss the point as you even queried it .......

Ah, interesting figures, now that I see them it seems obvious. But what "problem I assumed existed" is negated by multiple power feeds?
I said earlier .......
... but don't forget there can be multiple power feeds into the system along its length that negate the problem you assumed existed
there wont be single end fed very long electrified train systems .... I can almost guarantee they will have multiple DC feedpoints along the system
as is done here in Australia


So I took it for granted that there actually is an AC current, but I can't imagine there actually being, if the drift velocity of an electron is 8cm an hour and they're oscillating at 50Hz, then they're not going anywhere.
As far as I'm aware, the drift is still occurring over and above the oscillation, so there will still be a net movement in a given direction


I'm just trying to understand how if the electrons aren't really moving, also I'm trying to compare that to an equivalent DC I^2.R loss where the electrons in the transmission line do actually move.
The only thing I can conjure to explain this is that the electrons are actually moving very fast, because If I'm running an inverter then surely electrons are actually jumping over the junctions very fast.
no, they still have the same slow drift velocity

what junctions ???




Dave
 
  • #7
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ead my comment again you seemed to miss the point as you even queried it .......
I'm afraid you're going to have to humour me and spell it out, I have to many things running through my head (red herrings). I don't see what multiple feeds has to do with mitigating parasitic inductance? Does it have anything to do with increasing efficiency of transmission line (by breaking it up)? At first when I re-read what you wrote I thought 'oh because it has to be less than a quarter of the standing voltage wave at 50Hz, but that's 1500km, so the length of the line isn't an issue to AC.
there wont be single end fed very long electrified train systems .... I can almost guarantee they will have multiple DC feedpoints along the system
as is done here in Aus
Yeah I'm sure you're right.
As far as I'm aware, the drift is still occurring over and above the oscillation, so there will still be a net movement in a given direction
Huh, fascinating...and odd.
no, they still have the same slow drift velocity

what junctions ???
The PN junctions of a rectifier. Sorry for the confusion.

Yeah I'm really having difficulty understanding how AC current is actually flowing, maybe because I've always stuck with the theory and I've never married it to a physical model before, but hopefully I'll snap to my senses soon and realise I already understood it.

Cheers Dave!
 
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  • #8
davenn
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Yeah I'm really having difficulty understanding how AC current is actually flowing, maybe because I've always stuck with the theory and I've never married it to a physical model before, but hopefully I'll snap to my senses soon and realise I already understood it.
:smile: I don't claim to be an expert ... there's a good few guys on here that are way better than I, specially when it comes to the deeper theory

Just remember, in an AC circuit in particular, the energy isn't carried in the electrons but in the electromagnetic field that oscillates back and forward along the outside of the conductor. Electrons are accelerated back and forward. An accelerated charge, eg an electron, will radiate EM radiation

In a DC circuit, there is an initial pulse of an EM field through the circuit followed by the continuous flow of charge

It's the fast moving EM field that accounts for the near instantaneous light etc coming on when the power switch is initially turned on
The EM field is moving at the speed of light - the velocity factor of the cable. House power cabling will have a Vf of around 0.90 - 0.95 of the speed of light
a coaxial cable used for RF communications have various Vf's of between ~ 0.5 - 0.7 of the speed of light, depending of the construction of the cable
( types of insulation etc)


Dave
 
  • #9
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I do know what we are talking about Dave.I just couldn't understand Tim's wording in his first post and was under the impression he thinks certain way.

As for the multiple points of feeding the railway line it's true for all lines whether DC or AC , here I have a 70km line between capital city and where I live , the line uses 3kV DC yet it's fed atleast in 3 places that I know of , maybe more.

as for why the 25kV AC system over the 3Kv DC i'm not sure probably the 25kV ac system has more power and potential, otherwise the AC line actually introduces more complexity , older trains were almost all running with synchronous aka universal motors , they can be run on both DC and AC.
Wikipedia indeed says that newer trains use three phase asynchronous motors.
Although from a technical point of view the DC overhead line is simpler , we have some older trains running here with the overhead DC at 3kV, they have synchronous motors that are controlled using thyristors.


As much as I read Dave , AC in general has no net movement in any direction.As for what Tim is confused about , well I think that it doesn't matter whether the physical charge carriers get somewhere after time or not all it matters is that they make a movement, because current is measured as the amount of charge that passes through some given conducting area in a given amount of time , say second.
Much like Dave said , the fields carry the energy the electrons are just horses they ride.
As for energy , you can run from point A to B and that will mean your doing work yet you can run back and forth like they made you do in school gym class and your doing just as much of a work.


This thread inspired me to make my own as I too have some questions regarding electric trains, some of them came up while reading your posts.
 
  • #10
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I do know what we are talking about Dave.I just couldn't understand Tim's wording in his first post and was under the impression he thinks certain way.

As for the multiple points of feeding the railway line it's true for all lines whether DC or AC , here I have a 70km line between capital city and where I live , the line uses 3kV DC yet it's fed atleast in 3 places that I know of , maybe more.

as for why the 25kV AC system over the 3Kv DC i'm not sure probably the 25kV ac system has more power and potential, otherwise the AC line actually introduces more complexity , older trains were almost all running with synchronous aka universal motors , they can be run on both DC and AC.
Wikipedia indeed says that newer trains use three phase asynchronous motors.
Although from a technical point of view the DC overhead line is simpler , we have some older trains running here with the overhead DC at 3kV, they have synchronous motors that are controlled using thyristors.


As much as I read Dave , AC in general has no net movement in any direction.As for what Tim is confused about , well I think that it doesn't matter whether the physical charge carriers get somewhere after time or not all it matters is that they make a movement, because current is measured as the amount of charge that passes through some given conducting area in a given amount of time , say second.
Much like Dave said , the fields carry the energy the electrons are just horses they ride.
As for energy , you can run from point A to B and that will mean your doing work yet you can run back and forth like they made you do in school gym class and your doing just as much of a work.


This thread inspired me to make my own as I too have some questions regarding electric trains, some of them came up while reading your posts.
What's the link to the thread you started?
Also @Salvador you can send me your Faraday motor design if you still want a hand, I could use the practice.

Thinking about it, AC motors probably are much easier to control efficiently, but I wonder is it because now that we can control the frequency easily with solid-state technology, is the switch to AC trains just based on the fact that squirrel cage induction motors are really robust and you don't need to replace commutators all the time? (that is the main advantage?)
Also, I wonder, was there some problem with using wound rotor induction motors in the old days, (vary the resistance of the rotor to get maximum torque on start up)? Maybe it was too inefficient or they couldn't get resistors big enough, so they had to use DC motors instead? I may have to ask this in a new thread.

Cheers
 
  • #11
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haven't created the thread yet , need to focus a bit on it.
As for the Faraday thing , I though it through and sadly it won't work the exact way I envisioned.But that's for Pm.

as for the railway motors thing I hope someone else could come and help with that answer as I too would love to know.
 

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