# Electrical charge on Capacitor

## Homework Statement

A dc current of 3 A flows through an initially discharged capacitor.
After 2 micro s what is the electrical charge on the capacitor?

## Homework Equations

q(t)= integral i(t) dt between t=0 and t

## The Attempt at a Solution

(3t^2)/2=6x10^-12 C. Is this right?

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gneill
Mentor

## Homework Statement

A dc current of 3 A flows through an initially discharged capacitor.
After 2 micro s what is the electrical charge on the capacitor?

## Homework Equations

q(t)= integral i(t) dt between t=0 and t

## The Attempt at a Solution

(3t^2)/2=6x10^-12 C. Is this right?
Your relevant equation is okay, but it looks like you set up the integral incorrectly. What function did you integrate?

f(q)=i ?so integral of 3A which is (3t^2)/2 ?

gneill
Mentor
f(q)=i ?so integral of 3A which is (3t^2)/2 ?
Nope. Your function is a constant. Dropping units for now, I(t) = 3. There's no "t" in the function to become a $t^2$ upon integrating.

ye I was just being stupid, ty for the help