I am trying to set up intial conditions for an FEA simulation and I need to know the current density. I first need to get the current which is specified as a"constant current of 0.51 h rate." This is a disharge rate. I assumed that the h meant hour. Can I derive the currnet form that information?(adsbygoogle = window.adsbygoogle || []).push({});

Put another way, the paper said that the discharge occurs in steps of 1.1 (microAh) / ((cm^2)*(micrometer)) for 25 seconds and then maintianting an open circuit for 75 seconds. I am assuming this is just saying the 0.51 h rate another way. Can someone explain how I relate the two?

I used the 1.1 (microAh) / [(cm^2)*(micrometer)] to calculate the currnet density in A/m^2 by

[1.1 microAhr / ((10^-2)^2*(10^-6)) ] * [depth=10*10^-3] * [3600sec/hr * 1/25sec.]

= 15840 A/m^2.....this seemed kind of high, but I'm not an EE.

Any insights would be appreciated

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Electrical Current: hour rate

Loading...

Similar Threads for Electrical Current hour |
---|

UV light + electric current = boom? |

Electrical current question -- electrons moving through wires... |

High Current low Voltage |

**Physics Forums | Science Articles, Homework Help, Discussion**