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Frankboyle
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I've re-done my working out for Vo considering that 1/j=-j, am I correct?
If you suppress both sources, what does the resulting network look like? Is there any current path through the resistor?Frankboyle said:For the Thevenin Impedance, do I need to take into account the resistor from the left side of the circuit? Or just the impedance from the capacitor and inductor?
Correct. Note also that you previously determined that the short circuit effectively divides the circuit into two isolated circuits. You can ignore the current source subcircuit entirely for any behavior or properties of the voltage source subcircuit, and vice versa.Frankboyle said:If both sources are suppressed then there wouldn't be any current flowing through the resistor, so it shouldn't affect the Thevenin Impedance
##I_N = V_{th} / Z_{th}##. The Thevenin model must produce the same short-circuit behavior as the Norton model and the original circuit.johnwillbert82 said:So can it simply be a source transformation from your thevenins? with the new value for I being I=V/Z with Z being from the previous answer? and V being from the voltage source
No. The short still divides the two circuits.johnwillbert82 said:@gneill also do we now take into account the current source and resistor on the left? since there is no longer a short circuit, as there will now be a current source there
I'll need to see an attempt from the OP before I can sharejohnwillbert82 said:Thanks! Any idea for part D and E as I am stumped :(
Yes. Once you've got the Thevenin equivalent you can throw out the original circuit and never look at it againFrankboyle said:So as for the calculations, where I've previously used Zc, should I just use Zth to work out In?
We examined that before. How are those components connected to each other when the voltage supply is suppressed?Frankboyle said:I added the impedance of the capacitor and inductor, is this not the correct method?
A reactive network is a type of electrical circuit that contains components such as capacitors and inductors, which can store and release energy. These components cause the circuit to behave differently than a purely resistive circuit, resulting in a phenomenon known as reactance.
The reactance of a reactive network can be calculated using the formula X = 1/(2πfC) for capacitors and X = 2πfL for inductors, where X is the reactance in ohms, f is the frequency in hertz, C is the capacitance in farads, and L is the inductance in henrys.
Resistance is a measure of the opposition to current flow in a circuit, while reactance is a measure of the opposition to the change in current flow caused by the presence of reactive components. In other words, resistance affects the magnitude of current, while reactance affects the phase of current.
Reactive networks can cause a phase shift between voltage and current in a circuit, resulting in a difference between the apparent power and the real power. This can lead to power losses and decreased efficiency in the circuit.
Reactive networks are commonly used in electronic filters, power supplies, and AC power transmission systems. They are also essential in the design of radio frequency circuits and in the control of motor speed in industrial applications.