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Electrical Engineering - Transformers
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[QUOTE="cabraham, post: 5242639, member: 62772"] I used to design xfmrs. "S.F. = 0.90" means that the "stacking factor" value is 0.90. "SF" is the percentage of the wound metal tape that consists of ferromagnetic material. The tape is coated with an insulation layer on both sides. When the tape is wound some of the core volume is insulation and this contributes little to flux path. At high frequencies thinner tape is needed to keep eddy current losses low. But insulation thickness remains about constant. So for a 12-mil tape thickness, and a 0.4-mil insulation thickness on each surface of the tape, stacking factor can be computed as follows. The total tape thickness = 12 + 0.4 + 0.4 mils = 12.8mils. Of the 12.8 mils, 12 mils is actual ferrous material. So SF = 12/12.8 = 0.938. If the tape thickness was only 4 mils, needed for higher frequency operation, with 0.4-mil insulation thickness on each side, the stacking factor is 4 / (4 + 0.4 + 0.4) = 0.833. In general the thinner the tape, the lower the SF. Did I help? Regards. Claude [/QUOTE]
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