1. The problem statement, all variables and given/known data An alpha particle (charge equals +2e) is sent at high speed toward a gold nucleus (charge equals +79e). What is the electrical force acting on the alpha particle when it is (2.0 x 10-14) m from the gold nucleus? 2. Relevant equations I tried using Coulomb's law, which is E = k(q1q2/r2), with k = 9 x 109. 3. The attempt at a solution I attempted to use Coulomb's law, and plugged it in to get E = (9 x 109)(2e)(79e)/(2 x 10-14) and my answer was E= 2.6 x 1040 E is a repelling force The answer in my textbook is E=91 N and it is a repelling force (I got that part right at least!), and I would really like to know where I went wrong. I was thinking maybe by some chance I plugged it into my calculator wrong, but if someone could double check or tell me where I went wrong, that would be amazing. Thank you so much in advance.