Electrical Potential Homework: 3 Charges, 2 uC Each, 0.400m Sides

[stylez03]

Just to clarify

Total work for Charge 3 => U = Q*Vnew

Where Vnew = $$\frac {k(2Q)} {r}$$

$$U = Q * \frac {k(2Q)} {r}$$

I only ask because I'm low on tries since I've been working on this problem earlier.

 

[robb_]

Yes, now add that energy to the energy to bring in the second and first charges. (first one is zero)

 

[stylez03]

Yes, now add that energy to the energy to bring in the second and first charges. (first one is zero)

That's just $$U_{tot}$$ for Charge 3 right?

 

[robb_]

That will be the total energy associated with the charges-> the potential energy.

 

[stylez03]

That will be the total energy associated with the charges-> the potential energy.

Okay, potential energy, for the entire system am I correct?

 

[robb_]

yuppers if we are both talking tomatoes!