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**A constant voltage at a frequency of 1MHz is maintained across a circut consisting of the inductor in series with a variable capacitor. When the capacitor is set to 300pF the current has its max value. When the capacitor is reduced to 284pF the current is 0.707 of its ma value. Find**

**The inductance and the resistance of the inductor**

**Im not sure if im using the correct formula.**

f=[1/(2.pi)] x [1/(square root of (L).(C)]

f=frequency

L=Inductance

C=capacitance

L = 1/[(300x10^-12) x (2,000,000.pi)^2]

=337micro H

**What formula could I use to find the resistance of the inductor???**