# Electricity and Magnetism in a Thundercloud

1. Nov 27, 2007

### gt000

Magnetism and Potential Energy

1. The problem statement, all variables and given/known data

2. Relevant equations
U=$$\frac{k_{e}q_{1}q_{2}}{r}$$
E=$$\frac{F}{q}$$
V=$$\frac{U}{q}$$

$$k_{e}$$=8.99x10$$^{9}$$

3. The attempt at a solution
I have a start on the questions:
(a) Down
(b)i. Down
ii. Equal because the distance does not matter because they are on equipotential lines.
(c) I don't understand the question very well, but I said it was 0
(d) U=$$\frac{8.99x10^{9}*30*-30}{3}$$ = 2.697x10$$^{12}$$
(e) 0

I hope you guys can help me out.

Last edited: Nov 28, 2007